What are the solutions to the equation solvefor x,x^2-50y^2-10x+25=0 ?

The solutions to the equation solvefor x,x^2-50y^2-10x+25=0 are x=5(sqrt(2)y+1),x=5(-sqrt(2)y+1)

Find the zeros of solvefor x,x^2-50y^2-10x+25=0

The zeros of solvefor x,x^2-50y^2-10x+25=0 are x=5(sqrt(2)y+1),x=5(-sqrt(2)y+1)

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solve for

x, x^{2} - 50 y^{2} - 10 x + 25 = 0

x = 5 (2 y + 1), x = 5 (- 2 y + 1)

Solution steps

x^{2} - 50 y^{2} - 10 x + 25 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 10 x - 50 y^{2} + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 50 y ^{2} + 25 )}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot (- 50 y^{2} + 25) : 102 y

x_{1, 2} = \frac{- ( - 10 ) \pm 10 2 y}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 10 2 y}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 10 2 y}{2 \cdot 1}

x = \frac{- ( - 10 ) + 10 2 y}{2 \cdot 1} : 5 (2 y + 1)

x = \frac{- ( - 10 ) - 10 2 y}{2 \cdot 1} : 5 (- 2 y + 1)

The solutions to the quadratic equation are:

x = 5 (2 y + 1), x = 5 (- 2 y + 1)

x^{2} + 24 x + 132

x^{2} + 23 x + 132 = 0

x^{2} + 3 x - 22 = 0

0 = x^{2} - 14 x + 46

x, x^{2} + z^{2} = 0

What are the solutions to the equation solvefor x,x^2-50y^2-10x+25=0 ?
The solutions to the equation solvefor x,x^2-50y^2-10x+25=0 are x=5(sqrt(2)y+1),x=5(-sqrt(2)y+1)
Find the zeros of solvefor x,x^2-50y^2-10x+25=0
The zeros of solvefor x,x^2-50y^2-10x+25=0 are x=5(sqrt(2)y+1),x=5(-sqrt(2)y+1)