What are the solutions to the equation x^2+23x+132=0 ?

The solutions to the equation x^2+23x+132=0 are x=-11,x=-12

Find the zeros of x^2+23x+132=0

The zeros of x^2+23x+132=0 are x=-11,x=-12

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x^{2} + 23 x + 132 = 0

x = - 11, x = - 12

Solution steps

x^{2} + 23 x + 132 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 1 \cdot 132}{2 \cdot 1}

2 3^{2} - 4 \cdot 1 \cdot 132 = 1

x_{1, 2} = \frac{- 23 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 23 + 1}{2 \cdot 1}, x_{2} = \frac{- 23 - 1}{2 \cdot 1}

x = \frac{- 23 + 1}{2 \cdot 1} : - 11

x = \frac{- 23 - 1}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = - 11, x = - 12

x^{2} + 3 x - 22 = 0

0 = x^{2} - 14 x + 46

x, x^{2} + z^{2} = 0

9 = - 4 x^{2} - x

- a^{2} - 2 a + 3 = 0

What are the solutions to the equation x^2+23x+132=0 ?
The solutions to the equation x^2+23x+132=0 are x=-11,x=-12
Find the zeros of x^2+23x+132=0
The zeros of x^2+23x+132=0 are x=-11,x=-12