What are the solutions to the equation 1/3 x^2+1/4 x-3=0 ?

The solutions to the equation 1/3 x^2+1/4 x-3=0 are x=(-3+3sqrt(65))/8 ,x=(-3-3sqrt(65))/8

Find the zeros of 1/3 x^2+1/4 x-3=0

The zeros of 1/3 x^2+1/4 x-3=0 are x=(-3+3sqrt(65))/8 ,x=(-3-3sqrt(65))/8

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\frac{1}{3} x^{2} + \frac{1}{4} x - 3 = 0

x = \frac{- 3 + 3 65}{8}, x = \frac{- 3 - 3 65}{8}

Decimal Notation

x = 2.64834 \dots, x = - 3.39834 \dots

Solution steps

\frac{1}{3} x^{2} + \frac{1}{4} x - 3 = 0

Find Least Common Multiplier of

3, 4 : 12

Multiply by LCM=

12

\frac{1}{3} x^{2} \cdot 12 + \frac{1}{4} x \cdot 12 - 3 \cdot 12 = 0 \cdot 12

Simplify

4 x^{2} + 3 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 36 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 36) = 365

x_{1, 2} = \frac{- 3 \pm 3 65}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 3 65}{2 \cdot 4}, x_{2} = \frac{- 3 - 3 65}{2 \cdot 4}

x = \frac{- 3 + 3 65}{2 \cdot 4} : \frac{- 3 + 3 65}{8}

x = \frac{- 3 - 3 65}{2 \cdot 4} : \frac{- 3 - 3 65}{8}

The solutions to the quadratic equation are:

x = \frac{- 3 + 3 65}{8}, x = \frac{- 3 - 3 65}{8}

x, x^{2} + x y + y^{2} = 25

x, x^{2} + x y + y^{2} = 36

3 (7 x - 9) - (7 x - 9)^{2} = 0

x (x - 1) + 2 x - 2 = 0

(x + 2)^{2} - 6 = 30

What are the solutions to the equation 1/3 x^2+1/4 x-3=0 ?
The solutions to the equation 1/3 x^2+1/4 x-3=0 are x=(-3+3sqrt(65))/8 ,x=(-3-3sqrt(65))/8
Find the zeros of 1/3 x^2+1/4 x-3=0
The zeros of 1/3 x^2+1/4 x-3=0 are x=(-3+3sqrt(65))/8 ,x=(-3-3sqrt(65))/8