What are the solutions to the equation 2x^2+x=22x+11 ?

The solutions to the equation 2x^2+x=22x+11 are x=11,x=-1/2

Find the zeros of 2x^2+x=22x+11

The zeros of 2x^2+x=22x+11 are x=11,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + x = 22 x + 11

x = 11, x = - \frac{1}{2}

Decimal Notation

x = 11, x = - 0.5

Solution steps

2 x^{2} + x = 22 x + 11

Move

11

to the left side

2 x^{2} + x - 11 = 22 x

Move

22 x

to the left side

2 x^{2} - 21 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 2 ( - 11 )}{2 \cdot 2}

(- 21)^{2} - 4 \cdot 2 (- 11) = 23

x_{1, 2} = \frac{- ( - 21 ) \pm 23}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 23}{2 \cdot 2}, x_{2} = \frac{- ( - 21 ) - 23}{2 \cdot 2}

x = \frac{- ( - 21 ) + 23}{2 \cdot 2} : 11

x = \frac{- ( - 21 ) - 23}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 11, x = - \frac{1}{2}

2 x^{2} - 5 x = 33

x, 5 x^{2} + 5 y^{2} - 9 x - 14 y + 26 = 0

s, 3 a s^{2} - a n^{2} = 0

4 - 2 x - x^{2}

x^{2} + 18 x + 101 = 7

What are the solutions to the equation 2x^2+x=22x+11 ?
The solutions to the equation 2x^2+x=22x+11 are x=11,x=-1/2
Find the zeros of 2x^2+x=22x+11
The zeros of 2x^2+x=22x+11 are x=11,x=-1/2