What are the solutions to the equation 2x^2-5x=33 ?

The solutions to the equation 2x^2-5x=33 are x= 11/2 ,x=-3

Find the zeros of 2x^2-5x=33

The zeros of 2x^2-5x=33 are x= 11/2 ,x=-3

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2 x^{2} - 5 x = 33

x = \frac{11}{2}, x = - 3

Decimal Notation

x = 5.5, x = - 3

Solution steps

2 x^{2} - 5 x = 33

Move

33

to the left side

2 x^{2} - 5 x - 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 33 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 33) = 17

x_{1, 2} = \frac{- ( - 5 ) \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 17}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 17}{2 \cdot 2}

x = \frac{- ( - 5 ) + 17}{2 \cdot 2} : \frac{11}{2}

x = \frac{- ( - 5 ) - 17}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{11}{2}, x = - 3

x, 5 x^{2} + 5 y^{2} - 9 x - 14 y + 26 = 0

s, 3 a s^{2} - a n^{2} = 0

4 - 2 x - x^{2}

x^{2} + 18 x + 101 = 7

2 q^{2} - 150 q + 2425 = 0

What are the solutions to the equation 2x^2-5x=33 ?
The solutions to the equation 2x^2-5x=33 are x= 11/2 ,x=-3
Find the zeros of 2x^2-5x=33
The zeros of 2x^2-5x=33 are x= 11/2 ,x=-3