What are the solutions to the equation 2q^2-150q+2425=0 ?

The solutions to the equation 2q^2-150q+2425=0 are q=(5(15+sqrt(31)))/2 ,q=(5(15-sqrt(31)))/2

Find the zeros of 2q^2-150q+2425=0

The zeros of 2q^2-150q+2425=0 are q=(5(15+sqrt(31)))/2 ,q=(5(15-sqrt(31)))/2

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2 q^{2} - 150 q + 2425 = 0

q = \frac{5 ( 15 + 31 )}{2}, q = \frac{5 ( 15 - 31 )}{2}

Decimal Notation

q = 51.41941 \dots, q = 23.58058 \dots

Solution steps

2 q^{2} - 150 q + 2425 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 150 ) \pm ( - 150 ) ^{2} - 4 \cdot 2 \cdot 2425}{2 \cdot 2}

(- 150)^{2} - 4 \cdot 2 \cdot 2425 = 1031

q_{1, 2} = \frac{- ( - 150 ) \pm 10 31}{2 \cdot 2}

Separate the solutions

q_{1} = \frac{- ( - 150 ) + 10 31}{2 \cdot 2}, q_{2} = \frac{- ( - 150 ) - 10 31}{2 \cdot 2}

q = \frac{- ( - 150 ) + 10 31}{2 \cdot 2} : \frac{5 ( 15 + 31 )}{2}

q = \frac{- ( - 150 ) - 10 31}{2 \cdot 2} : \frac{5 ( 15 - 31 )}{2}

The solutions to the quadratic equation are:

q = \frac{5 ( 15 + 31 )}{2}, q = \frac{5 ( 15 - 31 )}{2}

- 4 n^{2} + 5 n + 9 = 0

r^{2} + 140 = 0

- 2 x^{2} - 4 x - 5 = 0

2 (10 - x)^{2} = 98

x^{2} - 17 x - 60 = 0

What are the solutions to the equation 2q^2-150q+2425=0 ?
The solutions to the equation 2q^2-150q+2425=0 are q=(5(15+sqrt(31)))/2 ,q=(5(15-sqrt(31)))/2
Find the zeros of 2q^2-150q+2425=0
The zeros of 2q^2-150q+2425=0 are q=(5(15+sqrt(31)))/2 ,q=(5(15-sqrt(31)))/2