What are the solutions to the equation -2x^2-4x-5=0 ?

The solutions to the equation -2x^2-4x-5=0 are x=-1-isqrt(3/2),x=-1+isqrt(3/2)

Find the zeros of -2x^2-4x-5=0

The zeros of -2x^2-4x-5=0 are x=-1-isqrt(3/2),x=-1+isqrt(3/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} - 4 x - 5 = 0

x = - 1 - i \frac{3}{2}, x = - 1 + i \frac{3}{2}

Solution steps

- 2 x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) ( - 5 )}{2 ( - 2 )}

Simplify

(- 4)^{2} - 4 (- 2) (- 5) : 26 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 6 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 6 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 4 ) - 2 6 i}{2 ( - 2 )}

x = \frac{- ( - 4 ) + 2 6 i}{2 ( - 2 )} : - 1 - i \frac{3}{2}

x = \frac{- ( - 4 ) - 2 6 i}{2 ( - 2 )} : - 1 + i \frac{3}{2}

The solutions to the quadratic equation are:

x = - 1 - i \frac{3}{2}, x = - 1 + i \frac{3}{2}

2 (10 - x)^{2} = 98

x^{2} - 17 x - 60 = 0

\frac{x + 2}{4} - \frac{x ^{2} - 4}{3} = 2 - \frac{x ^{2} + 2}{6}

\frac{1000}{100} = n^{2} - 54

x^{2} - 3 x = x + 1

What are the solutions to the equation -2x^2-4x-5=0 ?
The solutions to the equation -2x^2-4x-5=0 are x=-1-isqrt(3/2),x=-1+isqrt(3/2)
Find the zeros of -2x^2-4x-5=0
The zeros of -2x^2-4x-5=0 are x=-1-isqrt(3/2),x=-1+isqrt(3/2)