What are the solutions to the equation -2x^2+4x+9=11 ?

The solutions to the equation -2x^2+4x+9=11 are x=1

Find the zeros of -2x^2+4x+9=11

The zeros of -2x^2+4x+9=11 are x=1

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- 2 x^{2} + 4 x + 9 = 11

x = 1

Solution steps

- 2 x^{2} + 4 x + 9 = 11

Move

11

to the left side

- 2 x^{2} + 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) ( - 2 )}{2 ( - 2 )}

4^{2} - 4 (- 2) (- 2) = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 ( - 2 )}

x = \frac{- 4}{2 ( - 2 )}

\frac{- 4}{2 ( - 2 )} = 1

x = 1

The solution to the quadratic equation is:

x = 1

x^{2} + 5 + 4 = 0

3 (p + 1)^{2} = 81

2 r^{2} - 3 r - 2 = 0

0 = 4 x^{2} + 11 x + 7

- 3 = x^{2}

What are the solutions to the equation -2x^2+4x+9=11 ?
The solutions to the equation -2x^2+4x+9=11 are x=1
Find the zeros of -2x^2+4x+9=11
The zeros of -2x^2+4x+9=11 are x=1