What are the solutions to the equation 3(p+1)^2=81 ?

The solutions to the equation 3(p+1)^2=81 are p=3sqrt(3)-1,p=-3sqrt(3)-1

Find the zeros of 3(p+1)^2=81

The zeros of 3(p+1)^2=81 are p=3sqrt(3)-1,p=-3sqrt(3)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (p + 1)^{2} = 81

p = 33 - 1, p = - 33 - 1

Decimal Notation

p = 4.19615 \dots, p = - 6.19615 \dots

Solution steps

3 (p + 1)^{2} = 81

Divide both sides by

3

(p + 1)^{2} = 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

p + 1 = 27 : p = 33 - 1

Solve

p + 1 = - 27 : p = - 33 - 1

The solutions to the quadratic equation are:

p = 33 - 1, p = - 33 - 1

2 r^{2} - 3 r - 2 = 0

0 = 4 x^{2} + 11 x + 7

- 3 = x^{2}

3 u^{2} + 21 u = 0

3 x^{2} - 8 x + 40 = 100

What are the solutions to the equation 3(p+1)^2=81 ?
The solutions to the equation 3(p+1)^2=81 are p=3sqrt(3)-1,p=-3sqrt(3)-1
Find the zeros of 3(p+1)^2=81
The zeros of 3(p+1)^2=81 are p=3sqrt(3)-1,p=-3sqrt(3)-1