What are the solutions to the equation 3x^2-8x+40=100 ?

The solutions to the equation 3x^2-8x+40=100 are x=6,x=-10/3

Find the zeros of 3x^2-8x+40=100

The zeros of 3x^2-8x+40=100 are x=6,x=-10/3

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3 x^{2} - 8 x + 40 = 100

x = 6, x = - \frac{10}{3}

Decimal Notation

x = 6, x = - 3.33333 \dots

Solution steps

3 x^{2} - 8 x + 40 = 100

Move

100

to the left side

3 x^{2} - 8 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 60 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 60) = 28

x_{1, 2} = \frac{- ( - 8 ) \pm 28}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 28}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 28}{2 \cdot 3}

x = \frac{- ( - 8 ) + 28}{2 \cdot 3} : 6

x = \frac{- ( - 8 ) - 28}{2 \cdot 3} : - \frac{10}{3}

The solutions to the quadratic equation are:

x = 6, x = - \frac{10}{3}

3 x^{2} + 12 + 9 = 0

50 - 2 x^{2} = 0

(4 x + 9)^{2} = 144

x^{2} + 11 = - 24

m^{2} + 4 m - 21 = 0

What are the solutions to the equation 3x^2-8x+40=100 ?
The solutions to the equation 3x^2-8x+40=100 are x=6,x=-10/3
Find the zeros of 3x^2-8x+40=100
The zeros of 3x^2-8x+40=100 are x=6,x=-10/3