What are the solutions to the equation (4x+9)^2=144 ?

The solutions to the equation (4x+9)^2=144 are x= 3/4 ,x=-21/4

Find the zeros of (4x+9)^2=144

The zeros of (4x+9)^2=144 are x= 3/4 ,x=-21/4

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(4 x + 9)^{2} = 144

x = \frac{3}{4}, x = - \frac{21}{4}

Decimal Notation

x = 0.75, x = - 5.25

Solution steps

(4 x + 9)^{2} = 144

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 9 = 144 : x = \frac{3}{4}

Solve

4 x + 9 = - 144 : x = - \frac{21}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{21}{4}

x^{2} + 11 = - 24

m^{2} + 4 m - 21 = 0

4 (x - 2)^{2} = 36

3 x (2 x + 5) - 6 (3 - x) (x - 1) = 14 x (x - 1)

3 + x = x^{2} + 3 x

What are the solutions to the equation (4x+9)^2=144 ?
The solutions to the equation (4x+9)^2=144 are x= 3/4 ,x=-21/4
Find the zeros of (4x+9)^2=144
The zeros of (4x+9)^2=144 are x= 3/4 ,x=-21/4