What are the solutions to the equation 4(x-2)^2=36 ?

The solutions to the equation 4(x-2)^2=36 are x=5,x=-1

Find the zeros of 4(x-2)^2=36

The zeros of 4(x-2)^2=36 are x=5,x=-1

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4 (x - 2)^{2} = 36

x = 5, x = - 1

Solution steps

4 (x - 2)^{2} = 36

Divide both sides by

4

(x - 2)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 9 : x = 5

Solve

x - 2 = - 9 : x = - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

3 x (2 x + 5) - 6 (3 - x) (x - 1) = 14 x (x - 1)

3 + x = x^{2} + 3 x

- 4 x^{2} + 2 x - 3 = 0

y, x^{2} - 4 x y + 4 y^{2} + x - 12 y - 10 = 0

z^{2} - 10 z + 29 = 0

What are the solutions to the equation 4(x-2)^2=36 ?
The solutions to the equation 4(x-2)^2=36 are x=5,x=-1
Find the zeros of 4(x-2)^2=36
The zeros of 4(x-2)^2=36 are x=5,x=-1