What are the solutions to the equation -4x^2+2x-3=0 ?

The solutions to the equation -4x^2+2x-3=0 are x= 1/4-i(sqrt(11))/4 ,x= 1/4+i(sqrt(11))/4

Find the zeros of -4x^2+2x-3=0

The zeros of -4x^2+2x-3=0 are x= 1/4-i(sqrt(11))/4 ,x= 1/4+i(sqrt(11))/4

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- 4 x^{2} + 2 x - 3 = 0

x = \frac{1}{4} - i \frac{11}{4}, x = \frac{1}{4} + i \frac{11}{4}

Solution steps

- 4 x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 4 ) ( - 3 )}{2 ( - 4 )}

Simplify

2^{2} - 4 (- 4) (- 3) : 211 i

x_{1, 2} = \frac{- 2 \pm 2 11 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 11 i}{2 ( - 4 )}, x_{2} = \frac{- 2 - 2 11 i}{2 ( - 4 )}

x = \frac{- 2 + 2 11 i}{2 ( - 4 )} : \frac{1}{4} - i \frac{11}{4}

x = \frac{- 2 - 2 11 i}{2 ( - 4 )} : \frac{1}{4} + i \frac{11}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} - i \frac{11}{4}, x = \frac{1}{4} + i \frac{11}{4}

y, x^{2} - 4 x y + 4 y^{2} + x - 12 y - 10 = 0

z^{2} - 10 z + 29 = 0

x (x + 2) = 4

x^{2} - 6 = - 2 x

4 5^{2} + 2 4^{2} = x^{2}

What are the solutions to the equation -4x^2+2x-3=0 ?
The solutions to the equation -4x^2+2x-3=0 are x= 1/4-i(sqrt(11))/4 ,x= 1/4+i(sqrt(11))/4
Find the zeros of -4x^2+2x-3=0
The zeros of -4x^2+2x-3=0 are x= 1/4-i(sqrt(11))/4 ,x= 1/4+i(sqrt(11))/4