What are the solutions to the equation 45^2+24^2=x^2 ?

The solutions to the equation 45^2+24^2=x^2 are x=51,x=-51

Find the zeros of 45^2+24^2=x^2

The zeros of 45^2+24^2=x^2 are x=51,x=-51

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4 5^{2} + 2 4^{2} = x^{2}

x = 51, x = - 51

Solution steps

4 5^{2} + 2 4^{2} = x^{2}

Switch sides

x^{2} = 4 5^{2} + 2 4^{2}

Simplify

4 5^{2} + 2 4^{2} : 2601

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2601, x = - 2601

2601 = 51

- 2601 = - 51

x = 51, x = - 51

4 x^{2} - 5 x^{2} - 20 = 0

x^{2} - 7 x = - \frac{24}{4}

0.5 x^{2} + 3 x = - 3

5 x^{2} + 5 = 26 x

4 x^{2} - 21 x - 49 = 0

What are the solutions to the equation 45^2+24^2=x^2 ?
The solutions to the equation 45^2+24^2=x^2 are x=51,x=-51
Find the zeros of 45^2+24^2=x^2
The zeros of 45^2+24^2=x^2 are x=51,x=-51