What are the solutions to the equation 4x^2-5x^2-20=0 ?

The solutions to the equation 4x^2-5x^2-20=0 are x=2sqrt(5)i,x=-2sqrt(5)i

Find the zeros of 4x^2-5x^2-20=0

The zeros of 4x^2-5x^2-20=0 are x=2sqrt(5)i,x=-2sqrt(5)i

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4 x^{2} - 5 x^{2} - 20 = 0

x = 25 i, x = - 25 i

Solution steps

4 x^{2} - 5 x^{2} - 20 = 0

Move

20

to the right side

4 x^{2} - 5 x^{2} = 20

Add similar elements:

4 x^{2} - 5 x^{2} = - x^{2}

- x^{2} = 20

Divide both sides by

- 1

x^{2} = - 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 20, x = - - 20

- 20 = 25 i

- - 20 = - 25 i

x = 25 i, x = - 25 i

x^{2} - 7 x = - \frac{24}{4}

0.5 x^{2} + 3 x = - 3

5 x^{2} + 5 = 26 x

4 x^{2} - 21 x - 49 = 0

p^{2} - 2 p - 91 = 8

What are the solutions to the equation 4x^2-5x^2-20=0 ?
The solutions to the equation 4x^2-5x^2-20=0 are x=2sqrt(5)i,x=-2sqrt(5)i
Find the zeros of 4x^2-5x^2-20=0
The zeros of 4x^2-5x^2-20=0 are x=2sqrt(5)i,x=-2sqrt(5)i