What are the solutions to the equation 5x^2+5=26x ?

The solutions to the equation 5x^2+5=26x are x=5,x= 1/5

Find the zeros of 5x^2+5=26x

The zeros of 5x^2+5=26x are x=5,x= 1/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} + 5 = 26 x

x = 5, x = \frac{1}{5}

Decimal Notation

x = 5, x = 0.2

Solution steps

5 x^{2} + 5 = 26 x

Move

26 x

to the left side

5 x^{2} + 5 - 26 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 26 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

(- 26)^{2} - 4 \cdot 5 \cdot 5 = 24

x_{1, 2} = \frac{- ( - 26 ) \pm 24}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 24}{2 \cdot 5}, x_{2} = \frac{- ( - 26 ) - 24}{2 \cdot 5}

x = \frac{- ( - 26 ) + 24}{2 \cdot 5} : 5

x = \frac{- ( - 26 ) - 24}{2 \cdot 5} : \frac{1}{5}

The solutions to the quadratic equation are:

x = 5, x = \frac{1}{5}

4 x^{2} - 21 x - 49 = 0

p^{2} - 2 p - 91 = 8

\frac{1}{2} A = π x^{2}

4 x^{2} + 36 x = 0

x^{2} - 16 x + 37 = 0

What are the solutions to the equation 5x^2+5=26x ?
The solutions to the equation 5x^2+5=26x are x=5,x= 1/5
Find the zeros of 5x^2+5=26x
The zeros of 5x^2+5=26x are x=5,x= 1/5