What are the solutions to the equation 4x^2+36x=0 ?

The solutions to the equation 4x^2+36x=0 are x=0,x=-9

Find the zeros of 4x^2+36x=0

The zeros of 4x^2+36x=0 are x=0,x=-9

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4 x^{2} + 36 x = 0

x = 0, x = - 9

Solution steps

4 x^{2} + 36 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

3 6^{2} - 4 \cdot 4 \cdot 0 = 36

x_{1, 2} = \frac{- 36 \pm 36}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 36 + 36}{2 \cdot 4}, x_{2} = \frac{- 36 - 36}{2 \cdot 4}

x = \frac{- 36 + 36}{2 \cdot 4} : 0

x = \frac{- 36 - 36}{2 \cdot 4} : - 9

The solutions to the quadratic equation are:

x = 0, x = - 9

x^{2} - 16 x + 37 = 0

y, 6 x y^{2} + 2 x^{3} = 2 k

w^{2} + 14 w

w^{2} - 12 w - 12 = 0

t = 3 t^{2} + 2 t, \int_{0}^{2} t d t

What are the solutions to the equation 4x^2+36x=0 ?
The solutions to the equation 4x^2+36x=0 are x=0,x=-9
Find the zeros of 4x^2+36x=0
The zeros of 4x^2+36x=0 are x=0,x=-9