What are the solutions to the equation t=3t^2+2t,integral from 0 to 2 of t ?

The solutions to the equation t=3t^2+2t,integral from 0 to 2 of t are t=0,t=-1/3

Find the zeros of t=3t^2+2t,integral from 0 to 2 of t

The zeros of t=3t^2+2t,integral from 0 to 2 of t are t=0,t=-1/3

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t = 3 t^{2} + 2 t, \int_{0}^{2} t d t

t = 0, t = - \frac{1}{3}

Decimal Notation

t = 0, t = - 0.33333 \dots

Solution steps

t = 3 t^{2} + 2 t

Switch sides

3 t^{2} + 2 t = t

Move

t

to the left side

3 t^{2} + t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

1^{2} - 4 \cdot 3 \cdot 0 = 1

t_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- 1 + 1}{2 \cdot 3}, t_{2} = \frac{- 1 - 1}{2 \cdot 3}

t = \frac{- 1 + 1}{2 \cdot 3} : 0

t = \frac{- 1 - 1}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

t = 0, t = - \frac{1}{3}

5 x^{2} + 4 x - 10 = 0

x^{2} - 16 x + 35 = 0

x^{2} + (x + 2)^{2} = 10

\frac{5}{6} x - \frac{2}{9} x^{2} = 0

y^{2} - 72 = 0

What are the solutions to the equation t=3t^2+2t,integral from 0 to 2 of t ?
The solutions to the equation t=3t^2+2t,integral from 0 to 2 of t are t=0,t=-1/3
Find the zeros of t=3t^2+2t,integral from 0 to 2 of t
The zeros of t=3t^2+2t,integral from 0 to 2 of t are t=0,t=-1/3