What are the solutions to the equation 5x^2+4x-10=0 ?

The solutions to the equation 5x^2+4x-10=0 are x=(-2+3sqrt(6))/5 ,x=-(2+3sqrt(6))/5

Find the zeros of 5x^2+4x-10=0

The zeros of 5x^2+4x-10=0 are x=(-2+3sqrt(6))/5 ,x=-(2+3sqrt(6))/5

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5 x^{2} + 4 x - 10 = 0

x = \frac{- 2 + 3 6}{5}, x = - \frac{2 + 3 6}{5}

Decimal Notation

x = 1.06969 \dots, x = - 1.86969 \dots

Solution steps

5 x^{2} + 4 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 ( - 10 )}{2 \cdot 5}

4^{2} - 4 \cdot 5 (- 10) = 66

x_{1, 2} = \frac{- 4 \pm 6 6}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 6 6}{2 \cdot 5}, x_{2} = \frac{- 4 - 6 6}{2 \cdot 5}

x = \frac{- 4 + 6 6}{2 \cdot 5} : \frac{- 2 + 3 6}{5}

x = \frac{- 4 - 6 6}{2 \cdot 5} : - \frac{2 + 3 6}{5}

The solutions to the quadratic equation are:

x = \frac{- 2 + 3 6}{5}, x = - \frac{2 + 3 6}{5}

x^{2} - 16 x + 35 = 0

x^{2} + (x + 2)^{2} = 10

\frac{5}{6} x - \frac{2}{9} x^{2} = 0

y^{2} - 72 = 0

3 x (x - 7) = 0

What are the solutions to the equation 5x^2+4x-10=0 ?
The solutions to the equation 5x^2+4x-10=0 are x=(-2+3sqrt(6))/5 ,x=-(2+3sqrt(6))/5
Find the zeros of 5x^2+4x-10=0
The zeros of 5x^2+4x-10=0 are x=(-2+3sqrt(6))/5 ,x=-(2+3sqrt(6))/5