What are the solutions to the equation 0=-16t^2+16t+1000 ?

The solutions to the equation 0=-16t^2+16t+1000 are t=-(-1+sqrt(251))/2 ,t=(1+sqrt(251))/2

Find the zeros of 0=-16t^2+16t+1000

The zeros of 0=-16t^2+16t+1000 are t=-(-1+sqrt(251))/2 ,t=(1+sqrt(251))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 16 t^{2} + 16 t + 1000

t = - \frac{- 1 + 251}{2}, t = \frac{1 + 251}{2}

Decimal Notation

t = - 7.42148 \dots, t = 8.42148 \dots

Solution steps

0 = - 16 t^{2} + 16 t + 1000

Switch sides

- 16 t^{2} + 16 t + 1000 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 16 ) \cdot 1000}{2 ( - 16 )}

1 6^{2} - 4 (- 16) \cdot 1000 = 16251

t_{1, 2} = \frac{- 16 \pm 16 251}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 16 + 16 251}{2 ( - 16 )}, t_{2} = \frac{- 16 - 16 251}{2 ( - 16 )}

t = \frac{- 16 + 16 251}{2 ( - 16 )} : - \frac{- 1 + 251}{2}

t = \frac{- 16 - 16 251}{2 ( - 16 )} : \frac{1 + 251}{2}

The solutions to the quadratic equation are:

t = - \frac{- 1 + 251}{2}, t = \frac{1 + 251}{2}

4 x^{2} + 13 x - 3 = 0

x^{2} + x + 1 = 1

5^{2} + x^{2} = 1 1^{2}

9 x^{2} + 5 x - 4 = 0

- 2 x^{2} + 9 x = 4

What are the solutions to the equation 0=-16t^2+16t+1000 ?
The solutions to the equation 0=-16t^2+16t+1000 are t=-(-1+sqrt(251))/2 ,t=(1+sqrt(251))/2
Find the zeros of 0=-16t^2+16t+1000
The zeros of 0=-16t^2+16t+1000 are t=-(-1+sqrt(251))/2 ,t=(1+sqrt(251))/2