What are the solutions to the equation 9x^2+5x-4=0 ?

The solutions to the equation 9x^2+5x-4=0 are x= 4/9 ,x=-1

Find the zeros of 9x^2+5x-4=0

The zeros of 9x^2+5x-4=0 are x= 4/9 ,x=-1

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9 x^{2} + 5 x - 4 = 0

x = \frac{4}{9}, x = - 1

Decimal Notation

x = 0.44444 \dots, x = - 1

Solution steps

9 x^{2} + 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 9 ( - 4 )}{2 \cdot 9}

5^{2} - 4 \cdot 9 (- 4) = 13

x_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 5 + 13}{2 \cdot 9}, x_{2} = \frac{- 5 - 13}{2 \cdot 9}

x = \frac{- 5 + 13}{2 \cdot 9} : \frac{4}{9}

x = \frac{- 5 - 13}{2 \cdot 9} : - 1

The solutions to the quadratic equation are:

x = \frac{4}{9}, x = - 1

- 2 x^{2} + 9 x = 4

x^{2} = x + x

1^{2} + x^{2} = 5^{2}

3 y^{2} - 9 y = 0

7 x^{2} + 3 x - 5 = 0

What are the solutions to the equation 9x^2+5x-4=0 ?
The solutions to the equation 9x^2+5x-4=0 are x= 4/9 ,x=-1
Find the zeros of 9x^2+5x-4=0
The zeros of 9x^2+5x-4=0 are x= 4/9 ,x=-1