What are the solutions to the equation (x+7)(x-8)=0 ?

The solutions to the equation (x+7)(x-8)=0 are x=-7,x=8

Find the zeros of (x+7)(x-8)=0

The zeros of (x+7)(x-8)=0 are x=-7,x=8

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(x + 7) (x - 8) = 0

x = - 7, x = 8

Solution steps

(x + 7) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 7 = 0 or x - 8 = 0

Solve

x + 7 = 0 : x = - 7

Solve

x - 8 = 0 : x = 8

The solutions to the quadratic equation are:

x = - 7, x = 8

(\frac{1}{4})^{2} + x^{2} = 1

2 y^{2} + 6 y - 7 = 0

p, p^{2} = a^{3}

t, v = t^{2} - 38

5.6 - 7 - 5 x - 19.3 x^{2} = 0

What are the solutions to the equation (x+7)(x-8)=0 ?
The solutions to the equation (x+7)(x-8)=0 are x=-7,x=8
Find the zeros of (x+7)(x-8)=0
The zeros of (x+7)(x-8)=0 are x=-7,x=8