What is factor 10x^2+21x-10 ?

The solution to factor 10x^2+21x-10 is (5x-2)(2x+5)

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factor 10x^2+21x-10

factor

10 x^{2} + 21 x - 10

(5 x - 2) (2 x + 5)

Solution steps

10 x^{2} + 21 x - 10

Break the expression into groups

= (10 x^{2} - 4 x) + (25 x - 10)

Factor out

2 x

from

10 x^{2} - 4 x : 2 x (5 x - 2)

Factor out

5

from

25 x - 10 : 5 (5 x - 2)

= 2 x (5 x - 2) + 5 (5 x - 2)

Factor out common term

5 x - 2

= (5 x - 2) (2 x + 5)

\frac{3}{5} \cdot \frac{5}{3}

x^{2} - 6 x = 40

3 x^{2} - 7 x - 26 = 0

486 + 108 x + 6 x^{2}

2 \cdot 32

What is factor 10x^2+21x-10 ?
The solution to factor 10x^2+21x-10 is (5x-2)(2x+5)