What are the solutions to the equation 12x^2-4x=5 ?

The solutions to the equation 12x^2-4x=5 are x= 5/6 ,x=-1/2

Find the zeros of 12x^2-4x=5

The zeros of 12x^2-4x=5 are x= 5/6 ,x=-1/2

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12 x^{2} - 4 x = 5

x = \frac{5}{6}, x = - \frac{1}{2}

Decimal Notation

x = 0.83333 \dots, x = - 0.5

Solution steps

12 x^{2} - 4 x = 5

Move

5

to the left side

12 x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 12 ( - 5 )}{2 \cdot 12}

(- 4)^{2} - 4 \cdot 12 (- 5) = 16

x_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 16}{2 \cdot 12}, x_{2} = \frac{- ( - 4 ) - 16}{2 \cdot 12}

x = \frac{- ( - 4 ) + 16}{2 \cdot 12} : \frac{5}{6}

x = \frac{- ( - 4 ) - 16}{2 \cdot 12} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = - \frac{1}{2}

- t^{2} + 3 t + 27 = 0

x^{2} - 14 x + 49 = 0

2 x^{2} + 3 x + \frac{9}{8} = 0

2 (x^{2} + 9) = 26

- 10 x + 175 - 5 x^{2} = 0

What are the solutions to the equation 12x^2-4x=5 ?
The solutions to the equation 12x^2-4x=5 are x= 5/6 ,x=-1/2
Find the zeros of 12x^2-4x=5
The zeros of 12x^2-4x=5 are x= 5/6 ,x=-1/2