What are the solutions to the equation 9b^2-49=0 ?

The solutions to the equation 9b^2-49=0 are b= 7/3 ,b=-7/3

Find the zeros of 9b^2-49=0

The zeros of 9b^2-49=0 are b= 7/3 ,b=-7/3

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9 b^{2} - 49 = 0

b = \frac{7}{3}, b = - \frac{7}{3}

Decimal Notation

b = 2.33333 \dots, b = - 2.33333 \dots

Solution steps

9 b^{2} - 49 = 0

Move

49

to the right side

9 b^{2} = 49

Divide both sides by

9

b^{2} = \frac{49}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = \frac{49}{9}, b = - \frac{49}{9}

\frac{49}{9} = \frac{7}{3}

- \frac{49}{9} = - \frac{7}{3}

b = \frac{7}{3}, b = - \frac{7}{3}

0. 3^{2} + 0. 4^{2} = x^{2}

3 x (x - 3) = 3 - 9 x

t, 0 = 0 + 17.2 \cdot t + \frac{1}{2} (- 9.8) t^{2}

\frac{x ^{2}}{2} + \frac{13 x}{20} = \frac{3}{2}

\frac{1}{2} \cdot 2.1 \cdot v^{2} = 6.5

What are the solutions to the equation 9b^2-49=0 ?
The solutions to the equation 9b^2-49=0 are b= 7/3 ,b=-7/3
Find the zeros of 9b^2-49=0
The zeros of 9b^2-49=0 are b= 7/3 ,b=-7/3