What are the solutions to the equation completesquare-4x^2-72x-68=0 ?

The solutions to the equation completesquare-4x^2-72x-68=0 are x=-1,x=-17

Find the zeros of completesquare-4x^2-72x-68=0

The zeros of completesquare-4x^2-72x-68=0 are x=-1,x=-17

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- 4 x^{2} - 72 x - 68 = 0

x = - 1, x = - 17

Solution steps

- 4 x^{2} - 72 x - 68 = 0

Move

68

to the right side

- 4 x^{2} - 72 x = 68

Divide both sides by

- 4

\frac{- 4 x ^{2} - 72 x}{- 4} = \frac{68}{- 4}

x^{2} + 18 x = - 17

Rewrite in the form

(x + a)^{2} = b

(x + 9)^{2} = 64

For

the solutions are

f (x) = a, - a

Solve

x + 9 = 64 : x = - 1

Solve

x + 9 = - 64 : x = - 17

The solutions to the quadratic equation are:

x = - 1, x = - 17

x^{2} - 7 x + 12 = 0

3 x^{2} = x^{2} + 2

290 = \frac{9.81 \cdot t ^{2}}{2}

m x^{2} + (m - 2) x - (3 m - 1) = 0

x^{2} - \frac{2 3}{3} x + \frac{1}{3} = 0

What are the solutions to the equation completesquare-4x^2-72x-68=0 ?
The solutions to the equation completesquare-4x^2-72x-68=0 are x=-1,x=-17
Find the zeros of completesquare-4x^2-72x-68=0
The zeros of completesquare-4x^2-72x-68=0 are x=-1,x=-17