What are the solutions to the equation 3x^2-60x+279=0 ?

The solutions to the equation 3x^2-60x+279=0 are x=10+sqrt(7),x=10-sqrt(7)

Find the zeros of 3x^2-60x+279=0

The zeros of 3x^2-60x+279=0 are x=10+sqrt(7),x=10-sqrt(7)

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3 x^{2} - 60 x + 279 = 0

x = 10 + 7, x = 10 - 7

Decimal Notation

x = 12.64575 \dots, x = 7.35424 \dots

Solution steps

3 x^{2} - 60 x + 279 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 3 \cdot 279}{2 \cdot 3}

(- 60)^{2} - 4 \cdot 3 \cdot 279 = 67

x_{1, 2} = \frac{- ( - 60 ) \pm 6 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 60 ) + 6 7}{2 \cdot 3}, x_{2} = \frac{- ( - 60 ) - 6 7}{2 \cdot 3}

x = \frac{- ( - 60 ) + 6 7}{2 \cdot 3} : 10 + 7

x = \frac{- ( - 60 ) - 6 7}{2 \cdot 3} : 10 - 7

The solutions to the quadratic equation are:

x = 10 + 7, x = 10 - 7

3 v^{2} + 2 v - 8 = 0

x^{2} + 11 x = - 18

x^{2} - 18 x - 4 = 0

4 (\frac{5 - 3 y}{2})^{2} - 3 (\frac{5 - 3 y}{2}) y + 9 y^{2} = 15

x^{2} - 4.4 x = - 3.84

What are the solutions to the equation 3x^2-60x+279=0 ?
The solutions to the equation 3x^2-60x+279=0 are x=10+sqrt(7),x=10-sqrt(7)
Find the zeros of 3x^2-60x+279=0
The zeros of 3x^2-60x+279=0 are x=10+sqrt(7),x=10-sqrt(7)