What is (6a^{-2}+9a^2)/(3a^{-2)} ?

The solution to (6a^{-2}+9a^2)/(3a^{-2)} is 2+3a^4

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simplify (6a^{-2}+9a^2)/(3a^{-2)}

simplify

\frac{6 a ^{- 2} + 9 a ^{2}}{3 a ^{- 2}}

2 + 3 a^{4}

Solution steps

\frac{6 a ^{- 2} + 9 a ^{2}}{3 a ^{- 2}}

Multiply

3 a^{- 2} : \frac{3}{a ^{2}}

= \frac{6 a ^{- 2} + 9 a ^{2}}{\frac{3}{a ^{2}}}

6 a^{- 2} = \frac{6}{a ^{2}}

= \frac{\frac{6}{a ^{2}} + 9 a ^{2}}{\frac{3}{a ^{2}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{( \frac{6}{a ^{2}} + 9 a ^{2} ) a ^{2}}{3}

Join

\frac{6}{a ^{2}} + 9 a^{2} : \frac{6 + 9 a ^{4}}{a ^{2}}

= \frac{a ^{2} \frac{9 a ^{4} + 6}{a ^{2}}}{3}

Multiply

\frac{6 + 9 a ^{4}}{a ^{2}} a^{2} : 6 + 9 a^{4}

= \frac{6 + 9 a ^{4}}{3}

Factor

6 + 9 a^{4} : 3 (2 + 3 a^{4})

= \frac{3 ( 2 + 3 a ^{4} )}{3}

Divide the numbers:

\frac{3}{3} = 1

= 2 + 3 a^{4}

0. 3^{2}

\frac{p}{2} - 9 = 1

\frac{x + 2}{x + 4} > \frac{x - 3}{2 x - 1}

(8 a^{6} b^{\frac{3}{2}})^{\frac{2}{3}}

12 5^{b} = 5

What is (6a^{-2}+9a^2)/(3a^{-2)} ?
The solution to (6a^{-2}+9a^2)/(3a^{-2)} is 2+3a^4