What are the solutions to the equation 2y^2-7y+3=0 ?

The solutions to the equation 2y^2-7y+3=0 are y=3,y= 1/2

Find the zeros of 2y^2-7y+3=0

The zeros of 2y^2-7y+3=0 are y=3,y= 1/2

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2 y^{2} - 7 y + 3 = 0

y = 3, y = \frac{1}{2}

Decimal Notation

y = 3, y = 0.5

Solution steps

2 y^{2} - 7 y + 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 \cdot 3 = 5

y_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 2}, y_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 2}

y = \frac{- ( - 7 ) + 5}{2 \cdot 2} : 3

y = \frac{- ( - 7 ) - 5}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

y = 3, y = \frac{1}{2}

x, x^{2} - 8 x + 3 = 0

3 x^{2} + 19 x^{2} + 21 x + 5 = 0

- 2 x^{2} - 3 = 5 x^{2} + 25

x^{2} + 5 - 6 = 0

x^{2} + 7 x + 8 = 0

What are the solutions to the equation 2y^2-7y+3=0 ?
The solutions to the equation 2y^2-7y+3=0 are y=3,y= 1/2
Find the zeros of 2y^2-7y+3=0
The zeros of 2y^2-7y+3=0 are y=3,y= 1/2