What are the solutions to the equation (x+9)(4x-1)=0 ?

The solutions to the equation (x+9)(4x-1)=0 are x=-9,x= 1/4

Find the zeros of (x+9)(4x-1)=0

The zeros of (x+9)(4x-1)=0 are x=-9,x= 1/4

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(x + 9) (4 x - 1) = 0

x = - 9, x = \frac{1}{4}

Decimal Notation

x = - 9, x = 0.25

Solution steps

(x + 9) (4 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 9 = 0 or 4 x - 1 = 0

Solve

x + 9 = 0 : x = - 9

Solve

4 x - 1 = 0 : x = \frac{1}{4}

The solutions to the quadratic equation are:

x = - 9, x = \frac{1}{4}

8 n^{2} - 4 = 532

4 x^{2} - x - 7 = 0

x^{2} - 6 x + 8.5 = 0

w^{2} - 18 w

(x - (3 + 7)) (x - (3 - 7)) = 0

What are the solutions to the equation (x+9)(4x-1)=0 ?
The solutions to the equation (x+9)(4x-1)=0 are x=-9,x= 1/4
Find the zeros of (x+9)(4x-1)=0
The zeros of (x+9)(4x-1)=0 are x=-9,x= 1/4