What are the solutions to the equation 5x^2+25=0 ?

The solutions to the equation 5x^2+25=0 are x=sqrt(5)i,x=-sqrt(5)i

Find the zeros of 5x^2+25=0

The zeros of 5x^2+25=0 are x=sqrt(5)i,x=-sqrt(5)i

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5 x^{2} + 25 = 0

x = 5 i, x = - 5 i

Solution steps

5 x^{2} + 25 = 0

Move

25

to the right side

5 x^{2} = - 25

Divide both sides by

5

x^{2} = - 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 5, x = - - 5

- 5 = 5 i

- - 5 = - 5 i

x = 5 i, x = - 5 i

9 x^{2} + 24 x - 7 = 0

2 x^{2} = 3 x - 10

a, (a^{3} + 27) = (a + 3) (a^{2} + ma + 9)

6 x^{2} - 84 x + 228 = 0

x^{2} - 6 x + 12

What are the solutions to the equation 5x^2+25=0 ?
The solutions to the equation 5x^2+25=0 are x=sqrt(5)i,x=-sqrt(5)i
Find the zeros of 5x^2+25=0
The zeros of 5x^2+25=0 are x=sqrt(5)i,x=-sqrt(5)i