What are the solutions to the equation 2X^2-12X=0 ?

The solutions to the equation 2X^2-12X=0 are X=6,X=0

Find the zeros of 2X^2-12X=0

The zeros of 2X^2-12X=0 are X=6,X=0

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2 X^{2} - 12 X = 0

X = 6, X = 0

Solution steps

2 X^{2} - 12 X = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 \cdot 0 = 12

X_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 2}

Separate the solutions

X_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 2}, X_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 2}

X = \frac{- ( - 12 ) + 12}{2 \cdot 2} : 6

X = \frac{- ( - 12 ) - 12}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

X = 6, X = 0

5 x = 4 x^{2} - 2

y, (y + 1)^{2} = (2 - x) ln (x)

4 x^{2} - 6 x + 9

2 r^{2} + 8 r - 19 = 0

(- \frac{3}{2})^{2} + (\frac{1}{2})^{2} = r^{2}

What are the solutions to the equation 2X^2-12X=0 ?
The solutions to the equation 2X^2-12X=0 are X=6,X=0
Find the zeros of 2X^2-12X=0
The zeros of 2X^2-12X=0 are X=6,X=0