What are the solutions to the equation completesquare x^2+10x-1=0 ?

The solutions to the equation completesquare x^2+10x-1=0 are x=sqrt(26)-5,x=-sqrt(26)-5

Find the zeros of completesquare x^2+10x-1=0

The zeros of completesquare x^2+10x-1=0 are x=sqrt(26)-5,x=-sqrt(26)-5

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x^{2} + 10 x - 1 = 0

x = 26 - 5, x = - 26 - 5

Decimal Notation

x = 0.09901 \dots, x = - 10.09901 \dots

Solution steps

x^{2} + 10 x - 1 = 0

Move

1

to the right side

x^{2} + 10 x = 1

Rewrite in the form

(x + a)^{2} = b

(x + 5)^{2} = 26

For

the solutions are

f (x) = a, - a

Solve

x + 5 = 26 : x = 26 - 5

Solve

x + 5 = - 26 : x = - 26 - 5

The solutions to the quadratic equation are:

x = 26 - 5, x = - 26 - 5

2 (x + 1)^{2} + 7 = 1

m^{2} + 4 m + 8 = 0

x, (2 x + j^{3} y)^{2} - 6 - j^{12} = 0

0 = x^{2} - 2 x + 6

x^{2} - 20 x + 72 = - 3 x - 3 x

What are the solutions to the equation completesquare x^2+10x-1=0 ?
The solutions to the equation completesquare x^2+10x-1=0 are x=sqrt(26)-5,x=-sqrt(26)-5
Find the zeros of completesquare x^2+10x-1=0
The zeros of completesquare x^2+10x-1=0 are x=sqrt(26)-5,x=-sqrt(26)-5