What are the solutions to the equation 6x^2+12x-15=0 ?

The solutions to the equation 6x^2+12x-15=0 are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2

Find the zeros of 6x^2+12x-15=0

The zeros of 6x^2+12x-15=0 are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2

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6 x^{2} + 12 x - 15 = 0

x = \frac{- 2 + 14}{2}, x = - \frac{2 + 14}{2}

Decimal Notation

x = 0.87082 \dots, x = - 2.87082 \dots

Solution steps

6 x^{2} + 12 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 ( - 15 )}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 (- 15) = 614

x_{1, 2} = \frac{- 12 \pm 6 14}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 12 + 6 14}{2 \cdot 6}, x_{2} = \frac{- 12 - 6 14}{2 \cdot 6}

x = \frac{- 12 + 6 14}{2 \cdot 6} : \frac{- 2 + 14}{2}

x = \frac{- 12 - 6 14}{2 \cdot 6} : - \frac{2 + 14}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 14}{2}, x = - \frac{2 + 14}{2}

y, 4 x^{2} + 9 y^{2} = 36

1 8^{2} + 1 5^{2} = c^{2}

- 2 (x + 1) = (x - 1) (x - 8)

(300 + 10 x) (5 - 0.2 x) = 0

5 t^{2} - 4 t = 11

What are the solutions to the equation 6x^2+12x-15=0 ?
The solutions to the equation 6x^2+12x-15=0 are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2
Find the zeros of 6x^2+12x-15=0
The zeros of 6x^2+12x-15=0 are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2