What are the solutions to the equation (300+10x)(5-0.2x)=0 ?

The solutions to the equation (300+10x)(5-0.2x)=0 are x=-30,x=25

Find the zeros of (300+10x)(5-0.2x)=0

The zeros of (300+10x)(5-0.2x)=0 are x=-30,x=25

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(300 + 10 x) (5 - 0.2 x) = 0

x = - 30, x = 25

Solution steps

(300 + 10 x) (5 - 0.2 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

300 + 10 x = 0 or 5 - 0.2 x = 0

Solve

300 + 10 x = 0 : x = - 30

Solve

5 - 0.2 x = 0 : x = 25

The solutions to the quadratic equation are:

x = - 30, x = 25

5 t^{2} - 4 t = 11

x^{2} + 3 x = 270

7 x^{2} - 28 x + 17 = - 4

2 x^{2} + 14 = 16 x

x^{2} + x - 7 = 5

What are the solutions to the equation (300+10x)(5-0.2x)=0 ?
The solutions to the equation (300+10x)(5-0.2x)=0 are x=-30,x=25
Find the zeros of (300+10x)(5-0.2x)=0
The zeros of (300+10x)(5-0.2x)=0 are x=-30,x=25