What are the solutions to the equation m^2+96m+8/3 =0 ?

The solutions to the equation m^2+96m+8/3 =0 are m=(2(sqrt(5178)-72))/3 ,m=-(2(72+sqrt(5178)))/3

Find the zeros of m^2+96m+8/3 =0

The zeros of m^2+96m+8/3 =0 are m=(2(sqrt(5178)-72))/3 ,m=-(2(72+sqrt(5178)))/3

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m^{2} + 96 m + \frac{8}{3} = 0

m = \frac{2 ( 5178 - 72 )}{3}, m = - \frac{2 ( 72 + 5178 )}{3}

Decimal Notation

m = - 0.02778 \dots, m = - 95.97221 \dots

Solution steps

m^{2} + 96 m + \frac{8}{3} = 0

Multiply both sides by

3

3 m^{2} + 288 m + 8 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 288 \pm 28 8 ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

28 8^{2} - 4 \cdot 3 \cdot 8 = 45178

m_{1, 2} = \frac{- 288 \pm 4 5178}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- 288 + 4 5178}{2 \cdot 3}, m_{2} = \frac{- 288 - 4 5178}{2 \cdot 3}

m = \frac{- 288 + 4 5178}{2 \cdot 3} : \frac{2 ( 5178 - 72 )}{3}

m = \frac{- 288 - 4 5178}{2 \cdot 3} : - \frac{2 ( 72 + 5178 )}{3}

The solutions to the quadratic equation are:

m = \frac{2 ( 5178 - 72 )}{3}, m = - \frac{2 ( 72 + 5178 )}{3}

8 x^{2} = 4

80 = 80 t - 16 t^{2}

(22 + 3) x^{2} - (22 + 4) x + 2 = 0

x^{2} - 3 x - 24 = 0

\frac{1}{3} x^{2} = 16

What are the solutions to the equation m^2+96m+8/3 =0 ?
The solutions to the equation m^2+96m+8/3 =0 are m=(2(sqrt(5178)-72))/3 ,m=-(2(72+sqrt(5178)))/3
Find the zeros of m^2+96m+8/3 =0
The zeros of m^2+96m+8/3 =0 are m=(2(sqrt(5178)-72))/3 ,m=-(2(72+sqrt(5178)))/3