What are the solutions to the equation a^2+5=7 ?

The solutions to the equation a^2+5=7 are a=sqrt(2),a=-sqrt(2)

Find the zeros of a^2+5=7

The zeros of a^2+5=7 are a=sqrt(2),a=-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

a^{2} + 5 = 7

a = 2, a = - 2

Decimal Notation

a = 1.41421 \dots, a = - 1.41421 \dots

Solution steps

a^{2} + 5 = 7

Move

5

to the right side

a^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 2, a = - 2

y, x (x - y) + y (y - z) + z (z - x) = 1

- 3 x^{2} - 9 x = 0

4 x^{2} + 3 x = 0

4 m^{2} + 8 m + 3 = 0

21 x^{2} + 48 x - 144 = 0

What are the solutions to the equation a^2+5=7 ?
The solutions to the equation a^2+5=7 are a=sqrt(2),a=-sqrt(2)
Find the zeros of a^2+5=7
The zeros of a^2+5=7 are a=sqrt(2),a=-sqrt(2)