What are the solutions to the equation x^2+1/7 x-1/7 =0 ?

The solutions to the equation x^2+1/7 x-1/7 =0 are x=(-1+sqrt(29))/(14),x=(-1-sqrt(29))/(14)

Find the zeros of x^2+1/7 x-1/7 =0

The zeros of x^2+1/7 x-1/7 =0 are x=(-1+sqrt(29))/(14),x=(-1-sqrt(29))/(14)

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x^{2} + \frac{1}{7} x - \frac{1}{7} = 0

x = \frac{- 1 + 29}{14}, x = \frac{- 1 - 29}{14}

Decimal Notation

x = 0.31322 \dots, x = - 0.45608 \dots

Solution steps

x^{2} + \frac{1}{7} x - \frac{1}{7} = 0

Multiply both sides by

7

7 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

1^{2} - 4 \cdot 7 (- 1) = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 \cdot 7}, x_{2} = \frac{- 1 - 29}{2 \cdot 7}

x = \frac{- 1 + 29}{2 \cdot 7} : \frac{- 1 + 29}{14}

x = \frac{- 1 - 29}{2 \cdot 7} : \frac{- 1 - 29}{14}

The solutions to the quadratic equation are:

x = \frac{- 1 + 29}{14}, x = \frac{- 1 - 29}{14}

8 n^{2} + 47 n + 50 = - 3 n

[3 (x + 10)]^{2} + [3 x]^{2} = 20 0^{2}

\frac{3 x ^{2}}{8} = x - \frac{12}{24}

- 2 x^{2} + 7 x - 9 = 0

(x + 4) (x - 4) = 9

What are the solutions to the equation x^2+1/7 x-1/7 =0 ?
The solutions to the equation x^2+1/7 x-1/7 =0 are x=(-1+sqrt(29))/(14),x=(-1-sqrt(29))/(14)
Find the zeros of x^2+1/7 x-1/7 =0
The zeros of x^2+1/7 x-1/7 =0 are x=(-1+sqrt(29))/(14),x=(-1-sqrt(29))/(14)