What are the solutions to the equation -(1-t)^2=-25 ?

The solutions to the equation -(1-t)^2=-25 are t=-4,t=6

Find the zeros of -(1-t)^2=-25

The zeros of -(1-t)^2=-25 are t=-4,t=6

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- (1 - t)^{2} = - 25

t = - 4, t = 6

Solution steps

- (1 - t)^{2} = - 25

Divide both sides by

- 1

(1 - t)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 - t = 25 : t = - 4

Solve

1 - t = - 25 : t = 6

The solutions to the quadratic equation are:

t = - 4, t = 6

x^{2} + 3^{2} = 9^{2}

4.96 \cdot 1 0^{- 10} = 6.4 \cdot 1 0^{- 9} \cdot x^{2}

2 x^{2} + 6 x + \frac{1}{2} = 0

x, 19 x^{2} + 243 x y - 5 y^{2} - 527 = 0

10 x^{2} + 7 x + 4 = 0

What are the solutions to the equation -(1-t)^2=-25 ?
The solutions to the equation -(1-t)^2=-25 are t=-4,t=6
Find the zeros of -(1-t)^2=-25
The zeros of -(1-t)^2=-25 are t=-4,t=6