What are the solutions to the equation 2x^2+6x+1/2 =0 ?

The solutions to the equation 2x^2+6x+1/2 =0 are x=(-3+2sqrt(2))/2 ,x=-(3+2sqrt(2))/2

Find the zeros of 2x^2+6x+1/2 =0

The zeros of 2x^2+6x+1/2 =0 are x=(-3+2sqrt(2))/2 ,x=-(3+2sqrt(2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 6 x + \frac{1}{2} = 0

x = \frac{- 3 + 2 2}{2}, x = - \frac{3 + 2 2}{2}

Decimal Notation

x = - 0.08578 \dots, x = - 2.91421 \dots

Solution steps

2 x^{2} + 6 x + \frac{1}{2} = 0

Multiply both sides by

2

4 x^{2} + 12 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 1 = 82

x_{1, 2} = \frac{- 12 \pm 8 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 8 2}{2 \cdot 4}, x_{2} = \frac{- 12 - 8 2}{2 \cdot 4}

x = \frac{- 12 + 8 2}{2 \cdot 4} : \frac{- 3 + 2 2}{2}

x = \frac{- 12 - 8 2}{2 \cdot 4} : - \frac{3 + 2 2}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 2 2}{2}, x = - \frac{3 + 2 2}{2}

x, 19 x^{2} + 243 x y - 5 y^{2} - 527 = 0

10 x^{2} + 7 x + 4 = 0

6 p^{2} - 4 p - 5 = 0

(4 x - 7)^{2} + 13 = - 11

- x^{2} + 22 x + 112 = 0

What are the solutions to the equation 2x^2+6x+1/2 =0 ?
The solutions to the equation 2x^2+6x+1/2 =0 are x=(-3+2sqrt(2))/2 ,x=-(3+2sqrt(2))/2
Find the zeros of 2x^2+6x+1/2 =0
The zeros of 2x^2+6x+1/2 =0 are x=(-3+2sqrt(2))/2 ,x=-(3+2sqrt(2))/2