What are the solutions to the equation (4x-7)^2+13=-11 ?

The solutions to the equation (4x-7)^2+13=-11 are x= 7/4+isqrt(3/2),x= 7/4-isqrt(3/2)

Find the zeros of (4x-7)^2+13=-11

The zeros of (4x-7)^2+13=-11 are x= 7/4+isqrt(3/2),x= 7/4-isqrt(3/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(4 x - 7)^{2} + 13 = - 11

x = \frac{7}{4} + i \frac{3}{2}, x = \frac{7}{4} - i \frac{3}{2}

Solution steps

(4 x - 7)^{2} + 13 = - 11

Move

13

to the right side

(4 x - 7)^{2} = - 24

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 7 = - 24 : x = \frac{7}{4} + i \frac{3}{2}

Solve

4 x - 7 = - - 24 : x = \frac{7}{4} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{7}{4} + i \frac{3}{2}, x = \frac{7}{4} - i \frac{3}{2}

- x^{2} + 22 x + 112 = 0

x^{2} + 9 x - 360 = 0

2 g^{2} - 6 g - 9 = 0

(2 k - 1)^{2} = - 27

y, x = 4 - y^{2}

What are the solutions to the equation (4x-7)^2+13=-11 ?
The solutions to the equation (4x-7)^2+13=-11 are x= 7/4+isqrt(3/2),x= 7/4-isqrt(3/2)
Find the zeros of (4x-7)^2+13=-11
The zeros of (4x-7)^2+13=-11 are x= 7/4+isqrt(3/2),x= 7/4-isqrt(3/2)