What are the solutions to the equation 2g^2-6g-9=0 ?

The solutions to the equation 2g^2-6g-9=0 are g=(3(1+sqrt(3)))/2 ,g=(3(1-sqrt(3)))/2

Find the zeros of 2g^2-6g-9=0

The zeros of 2g^2-6g-9=0 are g=(3(1+sqrt(3)))/2 ,g=(3(1-sqrt(3)))/2

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2 g^{2} - 6 g - 9 = 0

g = \frac{3 ( 1 + 3 )}{2}, g = \frac{3 ( 1 - 3 )}{2}

Decimal Notation

g = 4.09807 \dots, g = - 1.09807 \dots

Solution steps

2 g^{2} - 6 g - 9 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 9) = 63

g_{1, 2} = \frac{- ( - 6 ) \pm 6 3}{2 \cdot 2}

Separate the solutions

g_{1} = \frac{- ( - 6 ) + 6 3}{2 \cdot 2}, g_{2} = \frac{- ( - 6 ) - 6 3}{2 \cdot 2}

g = \frac{- ( - 6 ) + 6 3}{2 \cdot 2} : \frac{3 ( 1 + 3 )}{2}

g = \frac{- ( - 6 ) - 6 3}{2 \cdot 2} : \frac{3 ( 1 - 3 )}{2}

The solutions to the quadratic equation are:

g = \frac{3 ( 1 + 3 )}{2}, g = \frac{3 ( 1 - 3 )}{2}

(2 k - 1)^{2} = - 27

y, x = 4 - y^{2}

0 = (x - 1) (x + 1)

w^{2} + 4 w - 96 = 0

16 = (x - 4) (x + 2)

What are the solutions to the equation 2g^2-6g-9=0 ?
The solutions to the equation 2g^2-6g-9=0 are g=(3(1+sqrt(3)))/2 ,g=(3(1-sqrt(3)))/2
Find the zeros of 2g^2-6g-9=0
The zeros of 2g^2-6g-9=0 are g=(3(1+sqrt(3)))/2 ,g=(3(1-sqrt(3)))/2