What are the solutions to the equation 11x^2+3x-12=0 ?

The solutions to the equation 11x^2+3x-12=0 are x=(-3+sqrt(537))/(22),x=(-3-sqrt(537))/(22)

Find the zeros of 11x^2+3x-12=0

The zeros of 11x^2+3x-12=0 are x=(-3+sqrt(537))/(22),x=(-3-sqrt(537))/(22)

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11 x^{2} + 3 x - 12 = 0

x = \frac{- 3 + 537}{22}, x = \frac{- 3 - 537}{22}

Decimal Notation

x = 0.91696 \dots, x = - 1.18969 \dots

Solution steps

11 x^{2} + 3 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 11 ( - 12 )}{2 \cdot 11}

3^{2} - 4 \cdot 11 (- 12) = 537

x_{1, 2} = \frac{- 3 \pm 537}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- 3 + 537}{2 \cdot 11}, x_{2} = \frac{- 3 - 537}{2 \cdot 11}

x = \frac{- 3 + 537}{2 \cdot 11} : \frac{- 3 + 537}{22}

x = \frac{- 3 - 537}{2 \cdot 11} : \frac{- 3 - 537}{22}

The solutions to the quadratic equation are:

x = \frac{- 3 + 537}{22}, x = \frac{- 3 - 537}{22}

4 x^{2} - 12 x + 9 = 0

4 x^{2} + 5 x - 4 = 0

(x - (2 + 5)) (x - (2 - 5)) = 0

4 m^{2} - 4 m + 17 = 0

6 x^{2} + 36 x + 36 = 0

What are the solutions to the equation 11x^2+3x-12=0 ?
The solutions to the equation 11x^2+3x-12=0 are x=(-3+sqrt(537))/(22),x=(-3-sqrt(537))/(22)
Find the zeros of 11x^2+3x-12=0
The zeros of 11x^2+3x-12=0 are x=(-3+sqrt(537))/(22),x=(-3-sqrt(537))/(22)