What are the solutions to the equation 4m^2-4m+17=0 ?

The solutions to the equation 4m^2-4m+17=0 are m= 1/2+2i,m= 1/2-2i

Find the zeros of 4m^2-4m+17=0

The zeros of 4m^2-4m+17=0 are m= 1/2+2i,m= 1/2-2i

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4 m^{2} - 4 m + 17 = 0

m = \frac{1}{2} + 2 i, m = \frac{1}{2} - 2 i

Solution steps

4 m^{2} - 4 m + 17 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 17}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 17 : 16 i

m_{1, 2} = \frac{- ( - 4 ) \pm 16 i}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- ( - 4 ) + 16 i}{2 \cdot 4}, m_{2} = \frac{- ( - 4 ) - 16 i}{2 \cdot 4}

m = \frac{- ( - 4 ) + 16 i}{2 \cdot 4} : \frac{1}{2} + 2 i

m = \frac{- ( - 4 ) - 16 i}{2 \cdot 4} : \frac{1}{2} - 2 i

The solutions to the quadratic equation are:

m = \frac{1}{2} + 2 i, m = \frac{1}{2} - 2 i

6 x^{2} + 36 x + 36 = 0

8 m^{2} + 48 m = 0

2 z^{2} - z + 1 = 0

z^{2} + 24 = 11 z

t, s = - 15.45 t^{2} - 1.302 t + 5.234

What are the solutions to the equation 4m^2-4m+17=0 ?
The solutions to the equation 4m^2-4m+17=0 are m= 1/2+2i,m= 1/2-2i
Find the zeros of 4m^2-4m+17=0
The zeros of 4m^2-4m+17=0 are m= 1/2+2i,m= 1/2-2i