What are the solutions to the equation m^2+4m+1=0 ?

The solutions to the equation m^2+4m+1=0 are m=-2+sqrt(3),m=-2-sqrt(3)

Find the zeros of m^2+4m+1=0

The zeros of m^2+4m+1=0 are m=-2+sqrt(3),m=-2-sqrt(3)

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m^{2} + 4 m + 1 = 0

m = - 2 + 3, m = - 2 - 3

Decimal Notation

m = - 0.26794 \dots, m = - 3.73205 \dots

Solution steps

m^{2} + 4 m + 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 1 = 23

m_{1, 2} = \frac{- 4 \pm 2 3}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 4 + 2 3}{2 \cdot 1}, m_{2} = \frac{- 4 - 2 3}{2 \cdot 1}

m = \frac{- 4 + 2 3}{2 \cdot 1} : - 2 + 3

m = \frac{- 4 - 2 3}{2 \cdot 1} : - 2 - 3

The solutions to the quadratic equation are:

m = - 2 + 3, m = - 2 - 3

- x^{2} + 3 x + 2

- x^{2} + 3 x + 4

v, v^{2} - 4 v + 4 = 0

- 1 x^{2} - 2 x + 3 = 0

r, A = \frac{1}{2} r^{2} θ

What are the solutions to the equation m^2+4m+1=0 ?
The solutions to the equation m^2+4m+1=0 are m=-2+sqrt(3),m=-2-sqrt(3)
Find the zeros of m^2+4m+1=0
The zeros of m^2+4m+1=0 are m=-2+sqrt(3),m=-2-sqrt(3)