What are the solutions to the equation 3x^2=-7x+136 ?

The solutions to the equation 3x^2=-7x+136 are x= 17/3 ,x=-8

Find the zeros of 3x^2=-7x+136

The zeros of 3x^2=-7x+136 are x= 17/3 ,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} = - 7 x + 136

x = \frac{17}{3}, x = - 8

Decimal Notation

x = 5.66666 \dots, x = - 8

Solution steps

3 x^{2} = - 7 x + 136

Move

136

to the left side

3 x^{2} - 136 = - 7 x

Move

7 x

to the left side

3 x^{2} - 136 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 7 x - 136 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 136 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 136) = 41

x_{1, 2} = \frac{- 7 \pm 41}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 41}{2 \cdot 3}, x_{2} = \frac{- 7 - 41}{2 \cdot 3}

x = \frac{- 7 + 41}{2 \cdot 3} : \frac{17}{3}

x = \frac{- 7 - 41}{2 \cdot 3} : - 8

The solutions to the quadratic equation are:

x = \frac{17}{3}, x = - 8

2 (x + 6) (x - 3) = 0

(x - 2)^{2} - (2 x + 3)^{2} = 80

x, 5 x^{2} + 2 x y - 2 y^{2} - x + 3 y + 6 = 0

- 6 p - 27 = - p^{2}

x^{2} - (a + d) x + (a d - b c) = 0

What are the solutions to the equation 3x^2=-7x+136 ?
The solutions to the equation 3x^2=-7x+136 are x= 17/3 ,x=-8
Find the zeros of 3x^2=-7x+136
The zeros of 3x^2=-7x+136 are x= 17/3 ,x=-8