What are the solutions to the equation 2(x+6)(x-3)=0 ?

The solutions to the equation 2(x+6)(x-3)=0 are x=-6,x=3

Find the zeros of 2(x+6)(x-3)=0

The zeros of 2(x+6)(x-3)=0 are x=-6,x=3

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2 (x + 6) (x - 3) = 0

x = - 6, x = 3

Solution steps

2 (x + 6) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 6 = 0 or x - 3 = 0

Solve

x + 6 = 0 : x = - 6

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - 6, x = 3

(x - 2)^{2} - (2 x + 3)^{2} = 80

x, 5 x^{2} + 2 x y - 2 y^{2} - x + 3 y + 6 = 0

- 6 p - 27 = - p^{2}

x^{2} - (a + d) x + (a d - b c) = 0

9 x^{2} - 5 x = 0

What are the solutions to the equation 2(x+6)(x-3)=0 ?
The solutions to the equation 2(x+6)(x-3)=0 are x=-6,x=3
Find the zeros of 2(x+6)(x-3)=0
The zeros of 2(x+6)(x-3)=0 are x=-6,x=3