What are the solutions to the equation 9x^2-5x=0 ?

The solutions to the equation 9x^2-5x=0 are x= 5/9 ,x=0

Find the zeros of 9x^2-5x=0

The zeros of 9x^2-5x=0 are x= 5/9 ,x=0

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9 x^{2} - 5 x = 0

x = \frac{5}{9}, x = 0

Decimal Notation

x = 0.55555 \dots, x = 0

Solution steps

9 x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

(- 5)^{2} - 4 \cdot 9 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 9}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 9}

x = \frac{- ( - 5 ) + 5}{2 \cdot 9} : \frac{5}{9}

x = \frac{- ( - 5 ) - 5}{2 \cdot 9} : 0

The solutions to the quadratic equation are:

x = \frac{5}{9}, x = 0

25 + 8 x - x^{2} = 0

x, x^{2} - y^{2} + z^{2} = 1

s, t = \frac{3}{5} s^{2} + 3 s + 1

7 x^{2} + 5 x - 8

- 2 x^{2} = 2

What are the solutions to the equation 9x^2-5x=0 ?
The solutions to the equation 9x^2-5x=0 are x= 5/9 ,x=0
Find the zeros of 9x^2-5x=0
The zeros of 9x^2-5x=0 are x= 5/9 ,x=0