What are the solutions to the equation (4x-6)^2=12 ?

The solutions to the equation (4x-6)^2=12 are x=(sqrt(3)+3)/2 ,x=(-sqrt(3)+3)/2

Find the zeros of (4x-6)^2=12

The zeros of (4x-6)^2=12 are x=(sqrt(3)+3)/2 ,x=(-sqrt(3)+3)/2

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(4 x - 6)^{2} = 12

x = \frac{3 + 3}{2}, x = \frac{- 3 + 3}{2}

Decimal Notation

x = 2.36602 \dots, x = 0.63397 \dots

Solution steps

(4 x - 6)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 6 = 12 : x = \frac{3 + 3}{2}

Solve

4 x - 6 = - 12 : x = \frac{- 3 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 3}{2}, x = \frac{- 3 + 3}{2}

4 x^{2} - 1.5 = 3.5

10 r^{2} - 2 r - 19 = 0

x^{2} - 18 x + 68 = 0

a^{2} + 7^{2} = 9^{2}

16 x^{2} = 64

What are the solutions to the equation (4x-6)^2=12 ?
The solutions to the equation (4x-6)^2=12 are x=(sqrt(3)+3)/2 ,x=(-sqrt(3)+3)/2
Find the zeros of (4x-6)^2=12
The zeros of (4x-6)^2=12 are x=(sqrt(3)+3)/2 ,x=(-sqrt(3)+3)/2