What are the solutions to the equation 4x^2+3=115 ?

The solutions to the equation 4x^2+3=115 are x=2sqrt(7),x=-2sqrt(7)

Find the zeros of 4x^2+3=115

The zeros of 4x^2+3=115 are x=2sqrt(7),x=-2sqrt(7)

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4 x^{2} + 3 = 115

x = 27, x = - 27

Decimal Notation

x = 5.29150 \dots, x = - 5.29150 \dots

Solution steps

4 x^{2} + 3 = 115

Move

3

to the right side

4 x^{2} = 112

Divide both sides by

4

x^{2} = 28

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 28, x = - 28

28 = 27

- 28 = - 27

x = 27, x = - 27

(y + 4)^{2} = 6

4 m^{2} + 9 = 0

(x + 1)^{2} = x^{2} + (x - 1)^{2}

x^{2} + 12 x + 36 = 0

x^{2} - 14 x = 24

What are the solutions to the equation 4x^2+3=115 ?
The solutions to the equation 4x^2+3=115 are x=2sqrt(7),x=-2sqrt(7)
Find the zeros of 4x^2+3=115
The zeros of 4x^2+3=115 are x=2sqrt(7),x=-2sqrt(7)